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Question

The general solution of 2cosx1=0 is

A
nπ+π3
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B
2nπ+π3
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C
2nπ±π3
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D
nππ3
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Solution

The correct option is C 2nπ±π3
Given 2cosx1=0
2cosx=1
cosx=12
cosx=cosπ3
x=2nπ±π3

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