The horizontal component of earth's magnetic field at a place is $\frac{1}{\sqrt{3}}$ times the vertical component. Determine the angle of dip at that place.

Q. The vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component the value of angle of dip at this place is

Q. At a certain place the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is

Q. At a place of Earth, the vertical component of Earth's magnetic field is $\sqrt{3}$ times its horizontal component. The angle of dip at this place is _____.

Q. At a place, the earth's horizontal component of magnetic field is $0.38\times {10}^{-4}\text{T}$. If the angle of dip at that place is ${60}^{\circ }$, then the vertical component of earth's magnetic field at that place will be approximately -