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Question

The horizontal range and maximum height attained by a projectile are R and H, respectively. If a constant horizontal acceleration a=g4 is imparted to the projectile due to wind, then its horizontal range and maximum height will be

A
(R+H),H2
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B
(R+H),2H
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C
(R+2H),H
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D
(R+H),H
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Solution

The correct option is D (R+H),H
H=u2sin2θ2g,R=u2sin2θg Maximum height will be same because acceleration a=g is in horizontal direction.
R=ucosθT+12aT2
Since time of flight, T=2usinθg
R=ucosθ(2usinθg)+12g4(2usinθg)2
R=R+12g4(2usinθg)2=R+H

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