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Question

The isotopes of an element have mass numbers A, A + 1, A + 2. The ratio of abundance of these isotopes is 3:2:4. Calculate the average atomic mass of the element.:

A
A+109
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B
A+910
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C
9A + 10
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D
10A + 9
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Solution

The correct option is C A+109
The average atomic mass of the element
=[3×A]+[2×(A+1)]+[4×(A+2)]3+2+4
=[3A]+[2A+2]+[4A+8]9
=9A+109
=A+109

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