The kinetic energy of an electron is nbsp-4-55 nbsp- nbsp-10-25 nbsp-J-The mass of electron is nbsp-9-1 nbsp-x nbsp-10-31 nbsp-kg nbsp-The nbsp-velocity of the electron is nbsp-102 nbsp-ms-1103 nbsp-ms-110 nbsp-ms-1

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Photoelectric Effect

The kinetic e...

Question

The kinetic energy of an electron is $4.55 \times 10^{- 25} J$ .The mass of electron is $9.1 x 10^{- 31} kg$ .The velocity of the electron is .

10^{2} {ms}^{- 1}

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10^{3} {ms}^{- 1}

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10 {ms}^{- 1}

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Solution

The correct option is B $10^{3} {ms}^{- 1}$
Calculation of the velocity of energy:
Kinetic energy $= \frac{1}{2} m v^{2} = 4.55 \times 10^{- 25} J$

$= 4.55 \times 10^{- 25} k g m^{2} s^{- 2}$

Or $v^{2} = \frac{2 \times K E}{m} = \frac{2 \times (4.55 \times 10^{- 25} k g m^{2} s^{- 2})}{(9.1 \times 10^{- 31} k g)}$

$= 10^{6} m^{2} s^{- 2}$

Or velocity $(v) = (10^{6} m^{2} s^{- 2})^{\frac{1}{2}} = 10^{3} m s^{- 1}$

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The kinetic energy of an electron is 4.55 × 10−25 J.The mass of electron is 9.1 x 10−31 kg .The velocity of the electron is .

The correct option is B 103 ms−1Calculation of the velocity of energy: Kinetic energy =12mv2=4.55×10−25 J =4.55×10−25k gm2s−2 Or v2=2×KEm=2×(4.55×10−25kg m2s−2)(9.1×10−31kg) =106m2s−2 Or velocity (v)=(106m2s−2)12=103ms−1

The kinetic energy of an electron is $4.55 \times 10^{- 25} J$ .The mass of electron is $9.1 x 10^{- 31} kg$ .The velocity of the electron is .