The length of a compound microscope is 14 cm and its magnifying power when final image is formed at near point is 25. If the focal length of eyepiece is 5 cm, the focal length of objective lens is:
A
5931 cm
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B
5925 cm
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C
2 cm
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D
1.5 cm
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Solution
The correct option is D 1.5 cm L=14cm,m=25Fe=5cm we know that L=v0+Fe⇒v0=L−Fe=9cm