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Standard XIII

Physics

Newton's Law of Gravitation

The magnitude...

Question

The magnitude of the gravitational force at distance $r_{1}$ and $r_{2}$ from the centre of a uniform sphere of radius R and mass M are $F_{1}$ and $F_{2}$ respectively. Then,

$\frac{F_{1}}{F_{2}} = \frac{r_{1}}{r_{2}} i f r_{1} < R a n d r_{2} < R$

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$\frac{F_{1}}{F_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} i f r_{1} > R a n d r_{2} > R$

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$\frac{F_{1}}{F_{2}} = \frac{r_{1}}{r_{2}} i f r_{1} > R a n d r_{2} > R$

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$\frac{F_{1}}{F_{2}} = \frac{r_{2}^{2}}{r_{1}^{2}} i f r_{1} < R a n d r_{2} < R$

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Solution

The correct option is B
$\frac{F_{1}}{F_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} i f r_{1} > R a n d r_{2} > R$

$g = \frac{4}{3} π ρ G r ∴\propto r i f r < R$

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The magnitude of the gravitational force at distance $r_{1}$ and $r_{2}$ from the centre of a uniform sphere of radius R and mass M are $F_{1}$ and $F_{2}$ respectively. Then,

The correct option is B
$\frac{F_{1}}{F_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} i f r_{1} > R a n d r_{2} > R$

$g = \frac{4}{3} π ρ G r ∴\propto r i f r < R$

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The magnitude of the gravitational force at distance r1 and r2 from the centre of a uniform sphere of radius R and mass M are F1 and F2 respectively. Then,

The correct option is B F1F2=r21r22 if r1>R and r2>R g=43πρGr ∴∝r if r<R

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The magnitude of the gravitational force at distance $r_{1}$ and $r_{2}$ from the centre of a uniform sphere of radius R and mass M are $F_{1}$ and $F_{2}$ respectively. Then,

The correct option is B
$\frac{F_{1}}{F_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} i f r_{1} > R a n d r_{2} > R$

$g = \frac{4}{3} π ρ G r ∴\propto r i f r < R$