The mass of BaCO3 produced when excess CO2 is bubbled through a solution of 0.205 mol Ba (OH)2 is

Q. The mass of $BaC{O}_3$ produced when excess $C{O}_2$ is bubbled through a solution of 0.205 mol $Ba(OH{)}_2$ is
molar mass of Ba=137 $gmo{l}^{-1}$

Q. The mass of $BaC{O}_3$ produced when excess of $C{O}_2$ is bubbled through a solution of $0.205\text{mole}Ba(OH{)}_2$ solution, is:
(Take molar mass of $Ba=137\text{g/mol}$)

$Ba(OH{)}_2+C{O}_2\to BaC{O}_3+H_{2}O$

Q. The mass of $BaC{O}_3$ produced when excess of $C{O}_2$ is bubbled through a solution of $0.205\text{mole}Ba(OH{)}_2$ solution, is:
(Take molar mass of $Ba=137\text{g/mol}$)

$Ba(OH{)}_2+C{O}_2\to BaC{O}_3+H_{2}O$

Q. The mass of $BaC{O}_3$ produced when excess $C{O}_2$ is bubbled through a solution of 0.205 mol $Ba(OH{)}_2$ is
molar mass of Ba=137 $gmo{l}^{-1}$

Q. When $C{O}_2$ is bubbled through a solution of barium peroxide in water: