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Question

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log[x/m]and logp gives a straight line with slope equal to 2and the intercept equal to 0.4771. The value of[x/m]at a pressure of 4atm is:(Givenlog3=0.4771)


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Solution

Step 1 : Given data

c=logk, x=2,k=3

c=log3=0.4771

Step 2: Apply absorbed equation

xm=kpx.....(1)

Take logarithm on both sides

logxm=logk+xlogp

Substitute the given values in the pressure equation

xm=3×(4)2

xm=48

Therefore the value for xm=48


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