The mass percentage composition of the elements in nitric acid are $H=1.59\%,$ $N=22.22\%,$ $O=76.19\%$ respectively.

$(H=1,N=14,O=16)$

The correct option is A True

Molecular formula of nitric acid $={HNO}_3$.

$\therefore$ Molecular mass of ${HNO}_3=1\times 1+14\times 1+16\times 3=63$

$\therefore$ Mass percentage of $H=\frac{1\times 1}{63}\times 100$%$=1.59$%

Mass percentage of $N=\frac{14\times 1}{63}\times 100$%$=1.59$%

Mass percentage of $O=\frac{16\times 3}{63}\times 100$%$=76.19$%

Answer is true.