The mass percentage of nitrogen in urea ( $N H_{2} C O N H_{2}$ )is:

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Solution

The correct option is B
Molecular mass of urea ( $N H_{2} C O N H_{2}$ ) is
= 2 $\times$ Atomic mass of N + 4 $\times$ (Atomic mass of H) + Atomic mass of C + Atomic mass of O = 60

Mass percentage of nitrogen = $\frac{Mass of an element}{Mass of compound} \times 100 = 46.67 %$

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