The masses of neutron and proton are $1.0087 a . m . u .$ and $1.0073 a . m . u .$ respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass $4.0015 a . m . u$ , then the binding energy fo the helium nucleus will be: ( $1 a . m . u . = 931 M e V$ )

28.4 M e V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20.8 M e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27.3 M e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.2 M e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $28.4 M e V$
$B . E . = Δ m c^{2}$
$= Δ \times 931 M e V = [2 (1.0087 + 1.0073) - 4.0015] \times 931 = 28.4 M e V$

Suggest Corrections

Similar questions

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu. The binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. Two protons and two neutrons combine to form a nucleus of

_{2} {H e}^{4}

. Find the energy released during the process. Take masses of proton, neutron and helium nuclues as

1.007 u, 1.009 u, 4.002 u

respectively.

Q. What is meant by binding energy of nucleus? Determine the binding energy per nucleon of an

α

particle if the masses of proton, neutron and

α

- particle are

1.00728 a m u

1.00867 a m u

and

4.00150 a m u

respectively.
(Given:

1 a m u = 931 M e V

)

Join BYJU'S Learning Program

The masses of neutron and proton are 1.0087a.m.u. and 1.0073a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015a.m.u, then the binding energy fo the helium nucleus will be: (1 a.m.u.=931MeV)

The correct option is A 28.4 MeVB.E.=Δmc2 =Δ×931 MeV=[2(1.0087+1.0073)−4.0015]×931=28.4 MeV

The masses of neutron and proton are $1.0087 a . m . u .$ and $1.0073 a . m . u .$ respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass $4.0015 a . m . u$ , then the binding energy fo the helium nucleus will be: ( $1 a . m . u . = 931 M e V$ )

The correct option is A $28.4 M e V$
$B . E . = Δ m c^{2}$
$= Δ \times 931 M e V = [2 (1.0087 + 1.0073) - 4.0015] \times 931 = 28.4 M e V$