The maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state is .

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Solution

The correct option is A 15
The number of lines produced when an electron from the $n^{t h}$ shell drops to the ground state is $\frac{n (n - 1)}{2}$

So the required number of emission lines is $\frac{6 (6 - 1)}{2} = 15$

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What is the maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state?

What is the maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state?

H - a t o m

n = 6

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