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Standard XII
Chemistry
Mean Free Path, Collision Frequency
The mean numb...
Question
The mean number of heads in three tosses of a coin is
A
3
2
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B
5
2
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C
1
2
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D
1
8
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Solution
The correct option is
A
3
2
We know that mean of binomial distibution is np here
n
=
3
,
P
=
1
2
,
.
So, mean
=
3
×
1
2
=
3
2
.
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0
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Q.
A biased coin with probability p, 0 < p < 1, of heads is tossed until a head appears for the first time. If the probability that the number of tosses required is even is 2/5, then p equals
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