The molal depression constant for water is ${1.86}^{\circ} C$ . The freezing point of a 0.05-molal solution of a non-electrolyte in water is

- {1.86}^{\circ} C

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- {0.93}^{\circ} C

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- {0.093}^{\circ} C

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- {0.93}^{\circ} C

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Solution

The correct option is C $- {0.093}^{\circ} C$
$Δ T f = K f \times M o l a l i t y = 1.86 \times 0.05 = 0.093$
Thus, freezing point = $0 - 0.093 = - {0.093}^{\circ} C$

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