the moles of KMnO4 require to oxidise 100ml of 1volume H2O2 in acidic medium is

Q. $100$ mL of $0.01M$ $KMn{O}_4$ oxidised $100$ mL $H_2{O}_2$ in acidic medium. The volume of same $KMn{O}_4$ required in strong alkaline medium to oxidise $100$ mL of same $H_2{O}_2$ is :

Q. $100$ mL of $1MKMn{O}_4$ oxidised $100$ mL of $H_2{O}_2$ in acidic medium (when ${Mn{O}_4}^{-}$ is reduced to $M{n}^{2+}$). Volume of same $KMn{O}_4$ required to oxidise $100$ mL of $H_2{O}_2$ in neutral medium (when ${Mn{O}_4}^{-}$ is reduced to $Mn{O}_2$) will be:

Q. In acidic medium, 100 ml of 1 M $KMn{O}_4$ solution oxidizes 100 ml of $H_2{O}_2$ solution. The volume of 0.01 M $KMn{O}_4$, required to oxidize the same volume of $H_2{O}_2$ in alkaline medium in ml is :

Q. $100$ mL of $0.01M$ $KMn{O}_4$ oxidized $100$ mL of $H_2{O}_2$ in acidic medium. The volume of the same $KMn{O}_4$ required in alkaline medium to oxidize $100$ mL of the same $H_2{O}_2$ will be :

Q. Assertion :The volume of 0.1M ${KMnO}_4$ required to oxidise 20 ml of 0.1 M oxalic acid in acidic medium is 20 ml. Reason: 2 moles of ${KMnO}_4$ = 5 moles of oxalic acid in acidic medium reaction.