The monthly pocket money of 50 students of a class are given in the following distribution- - Monthly-pocket-money-in-Rs- amp-0-50 amp-50-100 amp-100-150 amp-150-200 amp-200-250 amp-250-300- Number-of-students amp-2 amp-7 amp-8 amp-30 amp-12 amp-1- - Find the modal class and also give class mark of the modal class-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Class Interval

The monthly p...

Question

The monthly pocket money of 50 students of a class are given in the following distribution:

$\begin{matrix} M o n t h l y p o c k e t m o n e y (i n R s .) & 0 - 50 & 50 - 100 & 100 - 150 & 150 - 200 & 200 - 250 & 250 - 300 N u m b e r o f s t u d e n t s & 2 & 7 & 8 & 30 & 12 & 1 \end{matrix}$

Find the modal class and also give class mark of the modal class.

Open in App

Solution

As we know the class with maximum frequency is called modal class. Hence, the modal class in the above question is 150-200 as it has the highest frequency of 30.
Hence the class mark is: $\frac{150 + 200}{2}$ = 175

Suggest Corrections

Similar questions

Find the mean of the step deviations:
$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y (f_{i}) & C l a s s m a r k (x_{i}) & d_{i} = x_{i} - a & u_{i} = \frac{d_{i}}{h} 0 - 100 & 40 & 50 & - 200 & - 2 100 - 200 & 39 & 150 & - 100 & - 1 200 - 300 & 34 & 250 & 0 & 0 300 - 400 & 30 & 350 & 100 & 1 400 - 500 & 45 & 450 & 200 & 2 \end{matrix}$

Find the mean, median and mode of the following data: [CBSE 2013]

Class	0−50	50−100	100−150	150−200	200−250	250−300	300−350
Frequency	2	3	5	6	5	3	1

Q. Find the mean of the following frequency distribution using step deviation method:

Class interval	0-50	50-100	100-150	150-200	200-250	250-300
Frequency	17	35	43	40	21	24

Or, The mean of the following frequency distribution is 24. Find the value of P.

Class	0-10	10-20	20-30	30-40	40-50
Frequency	15	20	35	p	10

Q. The monthly profits (in Rs.) of 100 shops are distributed as follows:

Profits per shop:	0-50	50-100	100-50	150-200	200-250	250-300
No. shops:	12	18	27	20	17	6

Draw a histogram for the data and show the frequency polygon for it.

Q. In a class test, 50 students obtained marks as follows:

Marks obtained	0−20	20−40	40−60	60−80	80−100
Number of students	4	6	25	10	5

Find the modal class and the median class. [CBSE 2014]

Join BYJU'S Learning Program

The monthly pocket money of 50 students of a class are given in the following distribution: Monthly pocket money(in Rs.)0−5050−100100−150150−200200−250250−300Number of students27830121 Find the modal class and also give class mark of the modal class.

As we know the class with maximum frequency is called modal class. Hence, the modal class in the above question is 150-200 as it has the highest frequency of 30. Hence the class mark is: 150+2002 = 175

As we know the class with maximum frequency is called modal class. Hence, the modal class in the above question is 150-200 as it has the highest frequency of 30.
Hence the class mark is: $\frac{150 + 200}{2}$ = 175