The most general value of θ satisfying tanθ+tan(3π4+θ)=2 are
Simplifying it, tanθ+tanθ−1tanθ+1=2 tanθ(1+tanθ)+tanθ−1=2(1+tanθ) tan2θ=3 tanθ=√3=tanπ3 So, θ=nπ±π3