The nature of the precipitate formed when sodium hydroxide reacts with iron (II) sulphate is of

iron (III) hydroxide which is dirty green in colour and insoluble in excess of NaOH.

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iron (II) hydroxide which is dirty green in colour and insoluble in excess of NaOH.

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sodium sulphate which is yellow in colour and soluble in excess of NaOH.

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sodium sulphate which is dirty green in colour and soluble in excess of NaOH.

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Solution

The correct option is B
iron (II) hydroxide which is dirty green in colour and insoluble in excess of NaOH.

The reaction of sodium hydroxide with iron(II) sulphate is shown below:

$F e S O_{4} + 2 N a O H$ $\to$ $N a_{2} S O_{4} + F e (O H)_{2} (↓)$

The precipitated iron (II) hydroxide is dirty green in colour and is insoluble in excess of NaOH.

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