The number of atoms in 4-25 g of -NH-3 is approximately1- 10-232- 10-234- 10-236- 10-23

The correct option is D 6× 10^23∵ 17 gm NH_3 contains 6× 10^23 molecules of NH_3 ∴ 4.25 gm NH_3 contains =6× 10^23/17× 4.25 ∴ No. of atoms =6× 10^23× 4.25/17× ...

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Standard IX

Chemistry

Mole Concept

The number of...

Question

The number of atoms in 4.25 g of $N H_{3}$ is approximately

1 \times 10^{23}

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2 \times 10^{23}

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4 \times 10^{23}

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6 \times 10^{23}

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Solution

The correct option is D $6 \times 10^{23}$
$∵ 17 g m N H_{3}$ contains $6 \times 10^{23}$ molecules of $N H_{3}$
$∴ 4.25 g m N H_{3}$ contains $= \frac{6 \times 10^{23}}{17} \times 4.25$
$∴$ No. of atoms $= \frac{6 \times 10^{23} \times 4.25}{17} \times 4 = 6 \times 10^{23}$

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The number of atoms in 4.25 g of NH3 is approximately

The correct option is D 6×1023∵17gmNH3 contains 6×1023 molecules of NH3 ∴ 4.25 gmNH3 contains =6×102317×4.25 ∴ No. of atoms =6×1023×4.2517×4=6×1023

The number of atoms in 4.25 g of $N H_{3}$ is approximately

The correct option is D $6 \times 10^{23}$
$∵ 17 g m N H_{3}$ contains $6 \times 10^{23}$ molecules of $N H_{3}$
$∴ 4.25 g m N H_{3}$ contains $= \frac{6 \times 10^{23}}{17} \times 4.25$
$∴$ No. of atoms $= \frac{6 \times 10^{23} \times 4.25}{17} \times 4 = 6 \times 10^{23}$