The number of atoms present in $4.25grams$ of $N{H}_3$ is approximately

The number of molecules present in $4.25grams$ of $N{H}_3$ is approximately:

The number of atoms present in $4.25grams$ of $N{H}_3$ is pproximately

The number of atoms present in $4.25grams$ of $N{H}_3$ is approximately________.

The number of atoms present in 4.25 g of ${\text{NH}}_3$ is approximately $6.02\times {10}^{23}$.