The number of atoms present in $4.25grams$ of $N{H}_3$ is pproximately

The number of atoms present in $4.25grams$ of $N{H}_3$ is approximately

The number of molecules present in $4.25grams$ of $N{H}_3$ is approximately:

The number of atoms present in $4.25grams$ of $N{H}_3$ is approximately________.

The number of atoms present in 4.25 g of ${\text{NH}}_3$ is approximately $6.02\times {10}^{23}$.

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0\times {10}^{23}$ (b) $1.5\times {10}^{23}$
(c) $2.0\times {10}^{23}$ (d) $3.5\times {10}^{23}$