The number of carbon atoms present in a signature, if a signature written by carbon pencil weights $1.2 \times 10^{- 3} g$ is

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Solution

The correct option is B
No. of carbon atoms = $\frac{(1.2 \times 10^{- 3})}{12} \times N_{A} = 6.02 \times 10^{19}$

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Q. The number of carbon atoms present in a signature, if a signature written by carbon pencil weights

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The number of carbon atoms present in a signature, if a signature written by carbon pencil weighs $1.2 \times 10^{- 3}$ g is:

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A student puts his signature with graphite pencil. If the mass of carbon in the signature is 10⁻¹² g. Calculate the number of carbon atoms in the signature.

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The number of carbon atoms present in a signature, if a signature written by carbon pencil weights 1.2×10−3g is

The correct option is B No. of carbon atoms = (1.2×10−3)12×NA=6.02×1019

The number of carbon atoms present in a signature, if a signature written by carbon pencil weights $1.2 \times 10^{- 3} g$ is

The correct option is B
No. of carbon atoms = $\frac{(1.2 \times 10^{- 3})}{12} \times N_{A} = 6.02 \times 10^{19}$