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Question

The number of chloride ions which would be precipitated, when CrCl3.4NH3 is treated with silver nitrate solution:

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is C 1
Chromium has coordination number six.
Therefore to write its formula, we will first add the maximum number of neutral elements inside the coordination sphere.

Hence, the formula is [Cr(NH3)4Cl2]Cl.

As 1 Cl ion is available for dissociation only one Cl ion will precipitate when it reacts with AgNO3.

Hence, the correct option is (C).

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