The number of ions formed on dissolving one molecule of $F e S O_{4} (N H_{4})_{2} S O_{4} .6 H_{2} O$ is/are

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Solution

The correct option is C 5
The number of ions formed on dissolving one molecule of $F e S O_{4} (N H_{4})_{2} S O_{4} .6 H_{2} O$ are five. i.e. $F e^{2 +}$ , 2 mole of $S O_{4}^{2 -}$ ion, 2 mole of $N H_{4}^{+}$ ion.

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