The number of molecules present in - 8- grams of oxygen gas are- 6-022- 10-23- 3-011- 10-23- 12-044- 10-23- 1-55- 10-23-

The correct option is D 1.55× 10^23 The molar mass of oxygen gas is 32 g/mol. n=8g32g/mol=0.25 mol n=N_a6.022× 10^23 N_a = 0.25 × 6.022 × 10 ...

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Standard X

Chemistry

Mole Concept and Avogadro's Number

The number of...

Question

The number of molecules present in $8$ grams of oxygen gas are:

6.022 \times 10^{23}

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3.011 \times 10^{23}

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12.044 \times 10^{23}

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1.55 \times 10^{23}

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Solution

The correct option is D $1.55 \times 10^{23}$
The molar mass of oxygen gas is 32 g/mol.

$n = \frac{8 g}{32 g / m o l} = 0.25 m o l$

$n = \frac{N_{a}}{6.022 \times 10^{23}}$

$N_{a} = 0.25 \times 6.022 \times 10^{23} = 1.55 \times 10^{23}$ molecules

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The number of molecules present in 8 grams of oxygen gas are:

The correct option is D 1.55×1023The molar mass of oxygen gas is 32 g/mol.n=8g32g/mol=0.25 moln=Na6.022×1023Na=0.25×6.022×1023=1.55×1023 molecules

The number of molecules present in $8$ grams of oxygen gas are:

The correct option is D $1.55 \times 10^{23}$
The molar mass of oxygen gas is 32 g/mol.

$n = \frac{8 g}{32 g / m o l} = 0.25 m o l$

$n = \frac{N_{a}}{6.022 \times 10^{23}}$

$N_{a} = 0.25 \times 6.022 \times 10^{23} = 1.55 \times 10^{23}$ molecules