The octahedral complex $C o S O_{4} C l .5 N H_{3}$ exists in two isomeric forms X and Y. Isomer X reacts with $A g N O_{3}$ to give a white precipitate, but does not react with $B a C l_{2}$ . Isomer Y gives white precipitate with $B a C l_{2}$ but does not react with $A g N O_{3}$ . Isomer X and Y are

ionisation isomers

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linkage isomers

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coordination isomers

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solvate isomers

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Solution

The correct option is A ionisation isomers
Since X isomers reacts with $A g N O_{3}$ to give white ppt. so the X must be $[C o (N H_{3})_{5} S O_{4}] C l$
$[C o (N H_{3})_{5} S O_{4}] C l A g N O_{3} - --- \to A g C l ↓$
(X) (white ppt)
Simillarly since Y reacts with $B a C l_{2}$ to give white ppt and at the same time it also does not react with $A g N O_{3}$ , so the white white ppt. must be for $B a S O_{4}$ and hence Y will be $[C o (N H_{3})_{5} C l] S O_{4}$ .
$[C o (N H_{3})_{5} C l] S O_{4} B a C l_{2} - -- \to B a S O_{4} ↓$ (Y) (white ppt)
[X] and [Y] are ionisation isomers.

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Similar questions

Q. The octahedral complex

C o S O_{4} C l_{5} N H_{3}

exists in two isomeric forms

X

and

Y

. Isomers

X

reacts with

A g N O_{3}

to give a white precipitate, but does not react with

B a C l_{2}

. Isomer

Y

gives white precipitate with

B a C l_{2}

but does not react with

A g N O_{3}

.
Isomers

X

and

Y

are:

$C o S O_{4} C l .5 N H_{3}$ exists in two isomeric forms 'A and 'B'. Isomer 'A' reacts with $A g N O_{3}$ to give white precipitate, but does not react with $B a C l_{2} .$ Isomer 'B' gives white precipitate with $B a C l_{2}$ but does not react with $A g N O_{3} .$ Answer the following questions.
(a) Identify \A' and 'B' and white their structural formulae
(b) Name the type of isomerism involved.
(c) Give the IUPAC name of 'A' and 'B'.