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Byju's Answer
Standard XII
Chemistry
Bohrs Derivations
The orbital a...
Question
The orbital angular momentum of an electron in 2s-orbital is
A
+
1
2
,
h
2
π
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B
Zero
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C
h
2
π
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D
√
2
,
h
2
π
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Solution
The correct option is
B
Zero
Expression for orbital angular momentum (L) is
L
=
√
l
(
l
+
1
)
h
2
π
=
0
for 2s - electrons
∵
For s - orbital, l = 0
Suggest Corrections
0
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