The order of the oxidation state of the phosphorous atom in $H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}$ , and $H_{4} P_{2} O_{6}$ is

H_{3} P O_{4} > H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6}

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H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}

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H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6} > H_{3} P O_{4}

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H_{3} P O_{3} > H_{3} P O_{2} > H_{3} P O_{4} > H_{4} P_{2} O_{6}

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Solution

The correct option is B $H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}$
$H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}$
(+5) (-4) (-3) (+1)

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H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

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What is the acidic strength order of $H_{3} P O_{2}$ , $H_{3} P O_{3}$ , $H_{3} P O_{4}$ ? Why ?

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