The osmotic pressure at ${17}^{\circ }C$ of an aqueous solution containing $1.75g$ of sucrose per $150ml$ solution is:-

The correct option is A $0.8atm$
we have

mass of sucrose=1.75g

volume of solution=150ml

as $\pi v=nRT$

$\pi =\frac{n}{v}.RT$

$\pi =cRT$ $\because \frac{n}{v}=concentration$

Now,

$c=\frac{mole}{volume}$

$c=\frac{1.75\times 1000}{342\times 150}=0.0341$

Now,

from above formula

$\pi =0.0341\times 0.0821\times 290$

$\pi =0.811$