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Standard XII
Chemistry
Coordination and Oxidation Number
The oxidation...
Question
The oxidation state of Fe in browns ring complex
[
F
e
(
H
2
O
)
5
N
O
+
]
S
O
4
is:
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is
A
1
Let oxidation state of Fe =
x
x
+
5
(
0
)
+
1
+
(
−
2
)
=
0
x
+ 1 - 2= 0
x
= 1
The oxidation state of Fe in browns ring complex
[
F
e
(
H
2
O
)
5
N
O
+
]
S
O
4
is +1 as oxidation of NO is +1 and that of
S
O
−
2
4
is -2.
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Similar questions
Q.
The oxidation state of Fe in the brown ring complex
[
F
e
(
H
2
O
)
5
N
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]
S
O
4
is:
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The oxidation state of Fe in the 'Brown ring' complex
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The brown ring complex compound is formulated as
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e
(
H
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O
)
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Q.
The brown ring complex
[
F
e
(
H
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O
)
5
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O
+
]
S
O
4
has oxidation number of Fe as
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Q.
The oxidation state of
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