The oxidation states of $M n$ in $K_{2} M n O_{4}$ and $K M n O_{4}$ respectively are:

+ 6, + 7

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+ 6, + 6

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+ 7, + 7

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+ 7, + 6

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Solution

The correct option is A $+ 6, + 7$
Oxidation state of Mn in $M n O_{4}^{2 -}$ is +6 and the oxidation state of Mn in $M n O_{4}^{-}$ is +7.

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