The percentage of sulphur in an organic compound whose 0.32g produces 0.233g of $BaS{O}_4$ [atomic weight of Ba= 137, S=32] is

Q. The % of S in an organic compound whose 0.32g produces 0.233 g of BaSO4 is (Molar Mass of $BaS{O}_4$=233)

Q. 0.32g of organic compound in Carius method gave 0.233g of $BaS{O}_4$. The percentage of $S$ in the organic compound is:

Q. $0.16g$ of an organic compound containing sulphur produces $0.233g$ of $BaS{O}_4$. Percentage of sulphur in the compound is :

Q. $0.1254$g of an organic compound gave $0.1292$g of barium sulphate in the estimation of sulphur by Carius method. Find out the percentage of sulphur in the given organic compound.

Q. $0.32$ g of an aorganic compound gave $0.233$ g of $BaS{O}_4$. Determine the percentage of sulphur in the compound.
(At. mass of $Ba=137,S=32,O=16$)