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Addition Reaction

The phosphoru...

Question

The phosphorus present in an organic compound of mass 10 g is oxidized to phosphoric acid by heating with fuming nitric acid. The phosphoric acid so obtained is precipitated as $M g N H_{4} P O_{4}$ , which on ignition is converted into $M g_{2} P_{2} O_{7}$ . If the mass of Mg2P2O7 is 5 g, the percentage composition of phosphorus present in the sample of the organic compound is:

13.96

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14.96

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15.96

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12.96

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Solution

The correct option is A 13.96
The mass of the organic compound is 10 g.
Mass of $M g_{2} P_{2} O_{7}$ formed = 5 g
Molar mass of $M g_{2} P_{2} O_{7}$ = 222 g
P is estimated as $M g_{2} P_{2} O_{7}$ ,
Then, percentage of phosphorous = (62 x 5 x 100%)/(222 x 10) =13.96%

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