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Question

The power of a motor is 1600 watt. If the unit of mass is doubled and units of length and time are halved, the power of the motor in new system is:

A
400 units
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B
6400 units
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C
3200 units
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D
4800 units
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Solution

The correct option is B 6400 units
P=M1L2T3
P1P2=M11L21T31M12L22T32
Now,
M2=2M1,L2=12L1,T2=12T1P1P2=14P2=4P1
P2=4×1600=6400watt

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