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Byju's Answer

Standard XII

Physics

Transformer

The primary w...

Question

The primary winding of a transformer has $200$ turns and its secondary winding has $40$ turns. If the current in the secondary winding is $50 A$ , the current in the primary is

80 A

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10 A

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100 A

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160 A

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Solution

The correct option is B $10 A$
The number of turns in primary winding is $n_{1} = 200$
The number of turns in secondary winding is $n_{2} = 40$
The current in secondary winding is $I_{2} = 50 A$
Let the current in primary winding be $I_{1}$
We have $n_{1} I_{1} = n_{2} I_{2}$
$\Rightarrow I_{1} = \frac{40 \times 50}{200} = 10 A$
therefore option $B$ is correct

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The primary winding of a transformer has 200 turns and its secondary winding has 40 turns. If the current in the secondary winding is 50A, the current in the primary is

The correct option is B 10AThe number of turns in primary winding is n1=200The number of turns in secondary winding is n2=40The current in secondary winding is I2=50ALet the current in primary winding be I1We have n1I1=n2I2⇒I1=40×50200=10Atherefore option B is correct

The primary winding of a transformer has $200$ turns and its secondary winding has $40$ turns. If the current in the secondary winding is $50 A$ , the current in the primary is