The principle of a hydraulic press is that a smaller force applied on a larger piston results in a larger force acting on a smaller piston.

Q. In a hydraulic machine a force of 0.6 N acts normally on the smaller piston of area 0.2 m the force that acts on the larger piston whose area 200 m will be

Q. The average mass that must be lifted by a hydraulic press is 80 kg. If the radius of the larger piston is five times that of the smaller piston , what is the minimum force that must be applied?

Q. Figure shows a hydraulic press with the larger piston of diameter 35 cm at a height of 1.5 m relative to the smaller piston of diameter 10 cm.The mass on the smaller piston is 20 kg. What is the force exerted on the load by the larger piston. (The density of oil in the press is 750 kg/m${}^3$, g $=9.8m/s^2$).

Q. The areas of the pistons in a hydraulic machine are $5{cm}^2$ and $625{cm}^2$. What force on the smaller piston will support a load of $1250N$ on the larger piston?

Q. To lift an automobile of $1600kg$, a hydraulic pump with a larger piston $800c{m}^2$ in area is employed. If the area of the smaller piston is $10c{m}^2$. The force that must be applied on it is