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The range of ...

Question

The range of a projectile launched at an angle of $15^{\circ}$ with horizontal is $1.5 k m$ . The range of projectile when launched at an angle of $45^{\circ}$ to the horizontal is

A

6 k m

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B

0.75 k m

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C

3 k m

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D

1.5 k m

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Solution

The correct option is C $3 k m$
$R_{15} = \frac{u^{2}}{g} sin 2 \times 15^{\circ}$

$1.5 = \frac{u^{2}}{g} sin 30^{\circ}$

$\frac{u^{2}}{g} = \frac{1.5}{sin 30^{\circ}} = 1.5 \times 2 = 3 k m$

$R_{45} = \frac{u^{2}}{g} sin 2 \times 45^{\circ} = \frac{u^{2}}{g} = 3 k m$

Final answer: (b)

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