The ratio of mass percentage of carbon and hydrogen in an organic compound is
found to be $6:1$ and that between carbon and oxygen is $3:4$. The empirical formula of compound is:

The correct option is D $C{H}_{2}O$
Given the mass % ratio of H,C & O
$\text{Ratio}\frac{\text{\% C}}{\text{\% H}}=\frac{6}{1}\text{\&}\frac{\text{\% C}}{\text{\% O}}=\frac{3}{4}$
Ratio of $C,H\text{\&}O$ is $6:1:8$

	$C$	$H$	$O$
	$\frac{6}{12}$	$\frac{1}{1}$	$\frac{8}{16}$
$\text{Ratio of moles}$	$\frac{1}{2}$	$1$	$\frac{1}{2}$
	$1$	$2$	$1$

$\to$ Hence, the empirical formula of the compound is $C{H}_{2}O$.