The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is :

 AIEEE 2014

1 : 8

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1 : 4

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3 : 6

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7 : 32

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Solution

The correct option is D 7 : 32
Let mass of oxygen be 'W' g
therefore mass of nitrogen = 4W g
Moles of $O_{2} = \frac{W}{32} m o l$
Moles of $N_{2} = \frac{4 W}{28} m o l$
$∴$ $\frac{n_{O_{2}}}{n_{N_{2}}} = \frac{W}{32} \times \frac{28}{4 W} = \frac{7}{32}$
Thus, $\frac{n o . o f m o l e c u l e s o f O_{2}}{n o . o f m o l e c u l e s o f N_{2}} = \frac{7 \times N_{A}}{32 \times N_{A}} = \frac{7}{32}$

Hence the correct option is (d).

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The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is :  AIEEE 2014

The correct option is D 7 : 32Let mass of oxygen be 'W' g therefore mass of nitrogen = 4W g Moles of O2=W32 mol Moles of N2=4W28 mol ∴ nO2nN2=W32×284W=732 Thus, no. of molecules of O2no. of molecules of N2=7×NA32×NA=732 Hence the correct option is (d).

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is :

 AIEEE 2014