Primary, Secondary, Tertiary and Quaternary Carbon
The ratio of ...
Question
The ratio of the mass percentages of 'C and H' and C & O of a saturated acyclic organic compound 'X' are 4:1 and 3:4 respectively. Then, the moles of oxygen gas required for complete combustion of two moles of organic compound 'X' is:
A
5
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B
5.00
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C
5.0
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Solution
C:H=4:1 C:O=3:4
Mass ratio C:H:O12:3:16
Mole ratio: C:H:O1212:31:16161:3:1
Empirical formula =CH3O
Molecular formula =C2H6O2
(saturated acyclic organic compound)
General reaction: CxHyOz+(x+y4−z2)O2→xCO2+y2H2O C2H6O2+52O2→2CO2+3H2O
1 mol of organic compound reacts with 2.5 mol of oxygen
So,
2 moles of organic compound reacts with 5 moles of oxygen.