The rectangular components of a vector are $(2, 2) .$ The corresponding rectangular components of another vector are $(1, \sqrt{3}) .$ Find the angle between the two vectors.

\frac{5 π}{12}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{12}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3 π}{12}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{24}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{π}{12}$
let $\to a$ =(2,2) and b= $1, \sqrt{3}$
we need the angle between the two vectors let angle be \theta Then
$\to a$ . $\to b$ =abcos\theta
so $2 + \sqrt{3}$ = $(2, \sqrt{2})$ (2) $c o s θ$

so, $c o s θ$ = $\frac{1 + \sqrt{3}}{2 \sqrt{2}}$

so $θ$ = $c o s^{- 1} \frac{1 + \sqrt{3}}{2 \sqrt{2}}$ $= \frac{π}{12}$

Suggest Corrections

Similar questions

(2, 2)

(1, \sqrt{3})

(2, 2)

(1, \sqrt{3})

\to a

a_{1}, a_{2}, a_{3}

O X Y Z

y

\frac{π}{2}

\to a

Join BYJU'S Learning Program