The refractive index ( $μ$ ) of glass is found to have the values $1.49, 1.50, 1.52, 1.54 a n d 1.48$ . Calculate absolute error is each measurement.

Δ n_{5} = 1.51 - 1.48 = + 0.03

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Δ n_{4} = 1.51 - 1.54 = - 0.03

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Δ n_{3} = 1.51 - 1.52 = - 0.01

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All of these

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Solution

The correct option is B All of these
Mean =(1.49+1.50+1.52+1.54 +1.48)/5=1.506=1.51
Absolute error for each,
$Δ n_{1} = 1.51 - 1.49 = 0.02$
$Δ n_{2} = 1.51 - 1.50 = - 0.01$
$Δ n_{3} = 1.51 - 1.52 = - 0.01$
$Δ n_{4} = 1.51 - 1.54 = - 0.03$
$Δ n_{5} = 1.51 - 1.48 = + 0.03$

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