The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and $0.002768 S c m^{- 1}$ , respectively. When filled with 0.005 N $K_{2} S O_{4}$ , the solution had a resistance of 324 ohm. Calculate conductance of $K_{2} S O_{4}$ solution

3.086 \times 10^{- 3} S

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7.02 \times 10^{- 3} S

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5.04 \times 10^{- 3} S

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7.466 \times 10^{- 3} S

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Solution

The correct option is A $3.086 \times 10^{- 3} S$

From $K_{2} S O_{4}$ data:
R =324 ohm,
Conductance $G = \frac{1}{R} = \frac{1}{324} = 3.086 \times 10^{- 3} S$

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Similar questions

When a conductance cell was filled with 0.0025 M solution of $K_{2} S O_{4}$ , its resistance was 326 ohm. Length of cell =100cm and cross-sectional area $2.14 \times 10^{- 4} c m^{2}$ . The specific resistance of $K_{2} S O_{4}$ is:

Q. A conductivity cell, when filled with an aqueous solution of

0.02 M

K C l

25 ° C

, had a resistance of

250 ohm

. Its resistance, when filled with

6 \times 10^{- 5} M N H_{4} O H

solution was

10^{5}

ohm

. The specific conducatnce of

0.02 M

K C l

was

0.277 S m^{- 1}

. The molar ionic conductances at infinite dilution of

N H_{4}^{+} and O H^{-} ions are 73.4 \times 10^{- 4} and 198.0 \times 10^{- 4} S m^{2} m o l^{- 1},

respectively. Calculate the degree of dissociation of

6 \times 10^{- 5} M N H_{4} O H

solution:

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The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768Scm−1, respectively. When filled with 0.005 N K2SO4, the solution had a resistance of 324 ohm. Calculate conductance of K2SO4 solution

The correct option is A 3.086×10−3S From K2SO4 data: R =324 ohm, Conductance G=1R=1324=3.086×10−3S

The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and $0.002768 S c m^{- 1}$ , respectively. When filled with 0.005 N $K_{2} S O_{4}$ , the solution had a resistance of 324 ohm. Calculate conductance of $K_{2} S O_{4}$ solution

The correct option is A $3.086 \times 10^{- 3} S$

From $K_{2} S O_{4}$ data:
R =324 ohm,
Conductance $G = \frac{1}{R} = \frac{1}{324} = 3.086 \times 10^{- 3} S$