The resistance of N/10 KCl aqueous solution is 25ohm. If the electrodes in the cell are 4cm apart and area having 7cm^2 each, the molar conductance of the solution will be:

Q. The resistance of a N/10 KCI solution is 245$\Omega$. Calculate the equivalent conductance of the solution if the electrodes in the cell are 4cm apart and each having an area of 7.0sq,cm.

Q. The resistance of a $N/10$ KCl solution is 245 ohms. The specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. are :

Q. Each of the two platinum electrodes having area $64m{m}^2$ of a conductivity cell are separated by $8mm$. The resistance of the cell containing $7.5\times {10}^{-3}M$ $KCl$ solution at $298K$ is $1250ohm$. Calculate :
(i) Cell constant
(ii) Conductivity and
(iii) Molar conductivity

Q. In a conductivity cell the two platinum electrodes, each of area 10 sq. cm. are fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, the equivalent conductance of the salt solution will be:

Q. The resistance of $N/2$ solution of an electrolyte in a cell was found to be $45$ ohm. The equivalent conductivity of a solution, if the electrodes in the cell are $2.2$ cm apart and have an area of $3.8c{m}^2$ will be: