The smallest 3-digit number which is completely divisible by 18, 24 and 32 is

The correct option is C $288$
Note that the smallest 3-digit number which is completely divisible by 18, 24 and 32 is the LCM(Least Common Multiple) of the numbers 18, 24 and 32.Thus,
$\begin{array}{cc}2& 18,24,32\\ 3& 9,12,16\\ 2& 3,4,16\\ 2& 3,2,8\\ 2& 3,1,4\\ 2& 3,1,2\\ 3& 3,1,1\\ & 1,1,1\end{array}$
$⟹LCM=2\times 3\times 2\times 2\times 2\times 2\times 3=288$
Thus, the smallest 3-digit number which is completely divisible by 18, 24 and 32 is 288.