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Byju's Answer
Standard IX
Chemistry
Uses of Radioactive Substances
The starting ...
Question
The starting isotope and the end product isotope of actinium series are:
A
227
88
A
c
and
208
82
P
b
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B
235
92
U
and
207
82
P
b
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C
238
92
U
and
207
82
P
b
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D
235
92
U
and
208
82
P
b
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Solution
The correct option is
B
235
92
U
and
207
82
P
b
Actinium
(
4
n
+
3
)
series starts with
235
92
U
and as metal, decays finally to
207
82
P
b
.
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0
Similar questions
Q.
The isotope
235
92
U
decays in a number of steps to an isotope of
207
82
P
b
. The groups of particles emitted in this process will be:
Q.
235
92
U
decays with emission of
α
and
β
−
particles to form ultimately
207
82
P
b
. How many
α
−
and
β
−
particles are emitted per atom of
P
b
produced?
Q.
Estimate the age of a rock which is found to contain
5
×
10
−
5
mL of helium at STP and
3
×
10
−
7
g of uranium. (
T
50
of
238
92
U
is
4.51
×
10
9
yr and each
238
92
U
is converted into
206
82
P
b
Plan
238
92
U
⟶
206
82
P
b
+
6
β
+
8
α
(
h
e
l
i
u
m
)
We take the equation
[
[
P
b
]
[
U
]
+
1
]
=
(
2
)
y
where
[
P
b
]
[
U
]
is the molar ratio,
y
=
t
T
50
Q.
232
90
T
h
disintegrates to
208
82
P
b
. How many of
β
-particles are evolved?
Q.
The total number of
α
and
β
particles emitted in the nuclear reaction:
238
92
U
⟶
214
82
P
b
are:
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