The substitution reaction of propane with chlorine to form Octachloropropane nbsp-will occur in nbsp-1 step-4 steps-8 steps-7 steps-

The correct option is C 8 steps During the substitution reaction of propane nbsp;with chlorine, the chlorine atoms replace nbsp;one hydrogen in nbsp;each ...

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Standard X

Chemistry

Substitution Reaction

The substitut...

Question

The substitution reaction of propane with chlorine to form Octachloropropane will occur in

1 step

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4 steps

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8 steps

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7 steps

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Solution

The correct option is C
8 steps

During the substitution reaction of propane with chlorine, the chlorine atoms replace one hydrogen in each step. This continues till all hydrogen atoms are replaced by chlorine atoms and octa chloropropane is formed. Following reactions take place during the substitution reaction of propane with chlorine to form Octachloropropane:

(i) $C_{3} H_{8} (g) + C l_{2} (g) \to C_{3} H_{7} C l (g) + H C l (g)$

(ii) $C_{3} H_{7} C l (g) + C l_{2} (g) \to C_{3} H_{6} C l_{2} (g) + H C l (g)$

(iii) $C_{3} H_{6} C l_{2} (g) + C l_{2} (g) \to C_{3} H_{5} C l_{3} (g) + H C l (g)$

(iv) $C_{3} H_{5} C l_{3} + C l_{2} (g) \to C_{3} H_{4} C l_{4} (g) + H C l (g)$

(v) $C_{3} H_{4} C l_{4} (g) + C l_{2} (g) \to C_{3} H_{3} C l_{5} (g) + H C l (g)$

(vi) $C_{3} H_{3} C l_{5} (g) + C l_{2} (g) \to C_{3} H_{2} C l_{6} (g) + H C l (g)$

(vii) $C_{3} H_{2} C l_{6} (g) + C l_{2} (g) \to C_{3} H C l_{7} (g) + H C l (g)$

(viii) $C_{3} H C l_{7} (g) + C l_{2} (g) \to C_{3} C l_{8} (g) + H C l (g)$

Therefore, the substitution reaction of propane with chlorine to form Octachloropropane will occur in 8 steps.

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