The sum of all the natural numbers between 1 and 101 which are divisible by 5 is

1000

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1050

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1500

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2550

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Solution

The correct option is B
1050
$S u m = 5 + 10 + 15 + . . . . . . . . . . + 100$

$= 5 (Σ 20) = 5 \times \frac{20 \times 21}{2} = 1050$

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