The sum of the digits in the unit place of all the numbers formed with the help of $3, 4, 5, 6$ taken all at a time is-

18

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108

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432

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None of these

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Solution

The correct option is A $108$
Sum of the digits in the units place
$= (4 - 1)! (3 + 4 + 5 + 6)$
$= 3! (3 + 4 + 5 + 6)$
$= 6 \times 18$
$= 108$

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